mensuration Model Questions & Answers, Practice Test for ssc chsl tier 1 2024
ssc chsl tier 1 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Power, Indices And Surds
Time & Work
Time & Distance
Mensuration
If two corresponding sides of two similar triangles are in the ratio 9 : 4, then what is the ratio of their areas?
Answer: (a)
Given, ratio of sides = 9 : 4
By properties of two similar triangle,
${\text"Area of first triangle"}/{\text"Area of second triangle"} = {(9)^2}/{(4)^2} = {81}/{16}$ or 81 : 16
A cycle wheel makes 1000 revolutions is moving 440 m. What is the diameter of the wheel?
Answer: (c)
Distance travel in 1 revolution = ${440}/{1000}$ m
and circumference = π × d = ${44000}/{1000}$ cm
∴ d = ${44000 × 7}/{1000 × 22}$ = 14 cm
The cost of the paint is Rs. 36.50 per kg. If 1 kg of paint covers 16 square feet, how much will it cost to paint outside of a cube having 8 feet each side ?
Answer: (a)
Surface area of the cube = (6 × $8^2$) sq. ft. = 384 sq. ft.
Quantity of paint required = ${384}/{16}$ kg = 24 kg.
∴ Cost of painting = Rs.(36.50 × 24) = Rs.876.
What is the number of points in the plane of a ΔABC which are at equal distance from the vertices of the triangle?
Answer: (c)
Number of points is one, because circumcentre is the only point in the plane of a triangle, which is equidistant from the vertices of the triangle.
OA = OB = OC = r
If the area of a rectangle whose length is 5 more than twice its width is 75 sq units. What is the perimeter of the rectangle?
Answer: (b)
Let the width of the rectangle = x unit
Therefore, Length = (2 x + 5) unit
According to the question,
Area = x (2x + 5) ⇒ 75 = $2x^2$ + 5x
⇒ $2x^2$ + 5x – 75 = 0
⇒ $2x^2$ + 15x – 10x – 75 = 0
⇒ x (2x + 15) – 5(2x + 15) = 0
⇒ (2x + 15) (x – 5) = 0
⇒ x = 5 and ${- 15}/2$
Since, width cannot be negative
∴ width = 5 units and length = 2x + 5
= 2 × 5 + 5 = 15 units
∴ Perimeter of the rectangle = 2 (15 + 5) = 40 units
ssc chsl tier 1 2024 IMPORTANT QUESTION AND ANSWERS
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Mensuration Aptitude Questions Test: SSC CHSL 2024 Tier 1 »
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